25x^2-625=0

Solution for 25x^2-625=0 equation:

25x^2-625=0

a = 25; b = 0; c = -625;
Δ = b2-4ac
Δ = 02-4·25·(-625)
Δ = 62500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{62500}=250$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-250}{2*25}=\frac{-250}{50}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+250}{2*25}=\frac{250}{50}
=5
$